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5m^2+9m-23=0
a = 5; b = 9; c = -23;
Δ = b2-4ac
Δ = 92-4·5·(-23)
Δ = 541
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{541}}{2*5}=\frac{-9-\sqrt{541}}{10} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{541}}{2*5}=\frac{-9+\sqrt{541}}{10} $
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